1、題目Consider the state machine shown below, which has one inputwand one outputz.For this part, assume that a one-hot code is used with the state assignment y[6:1] 000001, 000010, 000100, 001000, 010000, 100000 for states A, B,..., F, respectively.Write a logic expression for the next-state signals Y2 and Y4. (Derive the logic equations by inspection assuming a one-hot encoding. The testbench will test with non-one hot inputs to make sure youre not trying to do something more complicated).2、分析獨(dú)熱碼只有一bit為1其它全為0。從A-F,即從next_state[1]-next_state[6]。拿A來(lái)說(shuō)從別的狀態(tài)到狀態(tài)A只有兩種情況A-A和D-A。對(duì)于B只有A能到B狀態(tài)。3、代碼module top_module ( input [6:1] y, input w, output Y2, output Y4); parameter A6b000001,B6b000010,C6b000100,D6b001000,E6b010000,F6b100000; reg [6:1]next_state; assign next_state[1]y[1]w||y[4]w; assign next_state[2]y[1](!w); assign next_state[3]y[2](!w)||y[6](!w); assign next_state[4]y[2]w||y[3]w||y[5]w||y[6]w; assign next_state[5]y[3](!w)||y[5](!w); assign next_state[6]y[4](!w); assign Y2next_state[2]; assign Y4next_state[4]; endmodule